Q:

An arena is hosting a rock concert. It has "silver" and "gold" seating sections. The event organizers are selling the first 100 gold tickets at the price of asilver ticket. The price of a silver ticket is $7 more than 1/2 the price of a gold ticket. The price of a silver ticket is $14 less than 6/5 the price of a gold ticket.How much will one of the first 100 buyers save on the price of a gold ticket?​

Accepted Solution

A:
Answer:s = the price of a silver ticketg = the price of a gold ticket s = 7 + (1/2)*g           (first relation)s = (6/5)*g - 14        (second relation)but (first relation) = (second relation) so we get7 + (1/2)*g = (6/5)*g - 14(6/5)*g - (1/2)*g = 7 + 14(7/10)*g = 21g = 30 from (first relation) we get s = 7 + (1/2)*30 = 22.how much would someone save? the answer is g - s = 8.Step-by-step explanation: